Reciprocal Correction with Black Rook  in Twomover Miniatures

 

by Robert Lincoln

 

 

These examples have reciprocal correction where Black’s rook is the star performer.

N1 R.Lincoln

"Fun with Chess Miniatures" 1996

 

#2

  The mechanism of No.1 is well-known, but that Black knight may provide a fair chance     for originality.  1.Qc3! (2.Qe3) provokes 1…R-file/Re5  2.Q(x)e5# and 1…R-rank/Rd4  2.Q(x)d4#.  The other defender contributes 1…Sc4  2.Qf3#.

 

 

N2  R.Lincoln

"Fun with Chess Miniatures" 1996

#2

 Some useful changed play occurs in No.2.  1.Be6? (zz) garners 1…R-file/Rg4 2.B(x)g4# and 1…Rxh4  2.Qd5#, but 1…Rf5!  Actually, 1.Qh3! (zz) substitutes 1…R-file/Rg4 2.Q(x)g4# and 1…Rxh4  2.Qf5#.  The remaining 1…R-rank/Rf7+ falls to 2.B(x)g6#.

 

 

N3  R.Lincoln

"More Fun with Chess Miniatures" 2000

#2

Obviously, White’s knight must start for No.3.  However, the logical 1.Sf7? (2.Qd8#) gets denied 1…Rb6+!  More exact is 1.Sc8! (zz) which promptly dispatches 1…R-rank/Re7  2.Qxe7# and 1…R-file/Rb6+  2.S(x)b6#.  One last desperate 1…Re8 brings 2.Qd6#.

 

 

N4 R.Lincoln

"Кудесник" 2001

#2

 Two nice peripheral offshoots are drawn from No.4.  1.Bc7! (zz) organizes the expected 1…R-file/Rd8  2.Q(x)d8#  and 1…R-rank/Re6  2.Q(x)e6#.  Bonus frills are 1…B~  2.S(x)b6# and 1…Bxc7  2.Qxc7#. 

 

N5 R.Lincoln

"Рыбинск-7 дней" 2005

#2

 The key of No.5 must insert a blocking move, else 1.Sf1? (zz) permits 1…Rh4!  Hence,  1.Sg4! (zz) suitably condemns that hapless rook to 1…R-file/Rd5  2.Q(x)d5# and 1…R-rank/Rh2  2.Q(x)h2#.

 

N6 R.Lincoln

"The Problemist" 2006

 

#2

  There are abundant tries and virtual activity in the beguiling No.6.  A waiting gesture like 1.Kf4? (zz) gives 1…Re1  2.Rxe1#, but 1…Kxf1!  1.Kg3? (zz) advances with 1…Kxf1  2.Qd3#, but 1…Rc3+!  1.Sd2? (2.Qe3#) transfers 2.Re1# for 1…Rc3, but 1…Rxf1!  1.Rd1? (2.Qd2, Sxc1#) gets refuted 1…Rxd1!  1.Rg1? (2.Qd2, Qe3, Sxc1#) is no better due to 1…Rxg1+!  The solution turns on 1.Bg1! (zz).  The customary formula follows after 1…R-rank/Rc4  2.Q(x)c4# or 1…R-file/Rd1  2.Q(x)d1#.  Then comes the best part.  Three “elimination” tactics attend 1…Re1  2.Rf2#, 1…Rxf1  2.Qd2#, and 1…Kxf1  2.Qf2#.  Altogether there are nine assorted mates.

 

 

N7  R.Lincoln

Original

 

#2

No.7 has the Black King’s sole guardian placed at an outlying position.  The reckless 1.Qc4+? catches 1…Ka3  2.Qb3#, but 1…Ka5!  1.Bd7+? destroys 1…Rc6  2.Bxc6#, but 1…Rxd7!  1.Sd5? (2.Qb4, Sc3, Bd1#) is also captured 1…Rxd5!  A more discreet 1.Se4? (2.Sc3#) is met 1…Rd3!  Ultimately, 1.Sd7! (zz) does the trick.  Now the besieged castle must glumly surrender to 1…R-rank/Rd1+  2.B(x)d1#, 1…R-file/Rb6  2.S(x)b6#, and 1…Rxd7  2.Bxd7#.

 

N8  R.Lincoln

Original

#2

Everything seems to be already set for No.8.  2.Qd8# pounces in the event of 1…Rxa7.  Nonetheless, something must be done about 1…a1Q!  1.Qxa2? proves no help because 1…Rxa7!  becomes playable.  So, 1.Qa6! (2.Qxb7#) applies a critical threat which alters 1…Rxa7 to 2.Qc8#.  The rest is apparent:  1…R-rank/Rb6+  2.S(x)b6# and 1…R-file/Rc7+  2.S(x)c7#.

 

N9 R.Lincoln

Original

#2  

One optimistic try accompanies No.9.  1.Bf7? zooms off hoping for 1…Sf1  2.Bh5#, but 1…Sg4!  Of course, the patient 1.Be6! (zz) adroitly settles the issue.  Results are 1…R-rank/Rd5  2.B(x)d5#, 1…R-file/Re3  2.R(x)e3#, and 1…S~  2.B(x)g4#.

 

N10  R.Lincoln

Original

#2

Another errant bishop try is featured in No.10.  1.Bh5? (2.Kxh6#) is obstructed by 1…Sf7!   Once again, a meticulous waiter carries the day.  1.Bd5! (zz) calmly anticipates 1…R-rank/Rc6  2.B(x)c6#, 1…R-file/Rd8  2.Q(x)d8#, and 1…S~  2.B(x)f7#. 

 

N11  R.Lincoln

Original

 #2

 Two passable tries augment No.11.  1.Qc4+? fetches 1…Rb4  2.Qa2# or 1…Ka5  2.Qxb5#, but 1…Ka3!  1.Bd6? (2.Qa3#) produces 1…Rb4  2.Qxb4#, but 1…Rb3! holds.  As usual, the quiet pause 1.Bc7! (zz) scores.  Derivatives are 1…R-rank/Rb6+  2.S(x)b6#, 1…R-file/Rc5+  2.S(x)c5#, and 1…Rb3  2.Qa5#.

 

N12  R.Lincoln

Original

#2

    In No.12, 1…Rd6! is a constant nemesis that copes with 1.Qc5? (2.Sc3#), 1.Qh5? (2.Qf3#), or 1.c4? (2.Qd5, Qg4, Qf4#).  The innocent 1.c3! (zz)  puts the boot to 1…R-rank/Re5  2.Q(x)e5# and 1…R-file/Rd6  2.S(x)d6#.   

 

 

Robert Lincoln

  

1.10.2012